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Question

A gun is fired at a target. At the moment of firing, the target is released and allowed to fall freely under gravity. Then the bullet :
[Assume initial aim to be precise]


A
misses the target by passing above it
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B
hits the target
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C
misses the target by passing below it
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D
may or may not hit the target
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Solution

The correct option is B hits the target
Initial velocity in downward direction of the target  $$u=0$$.
Also initial velocity in downward direction of the bullet  $$u=0$$
Thus distance covered by both in downward direction  $$S = ut+\dfrac{1}{2}gt^2$$
$$\implies$$  $$S = \dfrac{1}{2}gt^2$$
Thus both cover same distance in time $$t$$. Hence the bullet hits the target.

684440_518094_ans_80f5849211fa407b84c83b88e59468fa.png

Physics

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