A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ , find the total cost of carpeting the hall.

224

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264

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642

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292

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Solution

The correct option is A 224
Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs.224

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Similar questions

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per $m^{2}$ . Find the total cost of carpeting the hall.

Q. A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per

m^{2}

, find the total cost of carpeting the hall.

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A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per m2 , find the total cost of carpeting the hall.

The correct option is A 224Refer to the following figure: Area of parallelogram = Base × corresponding height = 8 × (1.75 × 8) = 112 m2 ​ Total cost of carpeting the hall = Cost per m2 ×​ Area = 2 × 112 = Rs.224

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ , find the total cost of carpeting the hall.

The correct option is A 224
Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs.224