The correct option is
A 952:715Since A has three shares in a lottery, his change of success means that he gets at least one prize, that is,he gets either one prize or 2 prizes or 3 prizes and his chance of failure means that he gets no prize.
It is certain that either he succeeds or fails.
If p denotes his chance of success and q the chance of his failure,then p+q=1 or p=1−q
We now find q.n=total no.of ways =12C3=12×11×101×2×3=220
Since out of 12 tickets in the lottery,he can draw any three tickets by virtue of his having three shares in the lottery and. m= favourable number of ways
=9C3=9×8×71×2×3=84,
Since he will fail to draw a prize if all the tickets drawn by him are blanks.∴q=mn=84220=2155.
∴p=A′s chance of success =1−2155=3455.
Similarly B's Chance of success p′=1−q′=1−6C28C2=1−6×58×7=1−1528=1328.
∴A′s chance of success ; B′s chance of success =p;p′=3455:1328=9521540:7151540=952:715.