Question

# A hawk of mass $10kg$ dives to catch a mouse. During dive it loses $500J$ of its potential energy. The height from where it begins its dive is (take $g=10m/{s}^{2}$)

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Solution

## Step 1. Given dataMass of the hawk $m=10kg$Change in gravitational potential energy $∆P{E}_{g}=500J$Step 2. Formula used$∆P{E}_{g}=mg∆h$where $m$ is the mass, $∆h$is the change in height $g$ is the gravitational constant.(take $g=10m/{s}^{2}$)Step 3. Find the heightLet the change in height be $∆h.$Then the change in height is $∆P{E}_{g}=mg∆h\phantom{\rule{0ex}{0ex}}⇒500=10×10×∆h\phantom{\rule{0ex}{0ex}}⇒∆h=5$Hence, the hawk will dive $5m$ to catch the mouse.

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