CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A helicopter of mass M is rising vertically upwards with a uniform acceleration a. If the mass of the persons in the helicopter is m, what is the magnitude and direction of the force exerted by the persons on the floor of the helicopter?


A

m(g+a) vertically downwards

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

m(g-a) vertically upwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

m(g+a) vertically upwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

m(g-a) vertically downwards

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

m(g+a) vertically downwards


Let N be the normal force exerted by the helicopter on the persons in vertically upward direction.
Since the persons are rising upwards with the helicopter with an acceleration a, Nmg=maN=m(g+a)
Hence, the force exerted by the people on the floor will be F=m(g+a) vertically downwards and the correct choice is (a).


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Losing Weight Using Physics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon