Question

A helium nucleus completes one revolution in a circular path of radius 0.8m in 2 seconds. The magnetic induction at the centre of the path will be

• A. $\frac{{10}^{-19}}{{\mu }_0}$
• B. ${10}^{-19}{\mu }_0$
• C. $\frac{2X{10}^{-19}}{{\mu }_0}$
• D. $2X{10}^{-19}{\mu }_0$

Answer 1

The correct option is B ${10}^{-19}{\mu }_0$

magnetic induction

=$\frac{{\mu }_{0}i}{2r}$

=$\frac{{\mu }_{0}qf}{2r}$

=$\frac{{\mu }_0\times 1.6\times {10}^{-19}\times 2\times 0.5}{2\times 0.8}$

=${10}^{-19}{\mu }_0$