Question

# A hemisphere bowl is made of steel, $$0.25\ cm$$ thick. the inner radius of the bowl is $$5\ cm$$. Find the outer curved surface area of the bowl.

Solution

## Given, Inner radius $$=5\ cm$$Outer radius $$=(5+0.25)\ cm=5.25\ cm$$Outer curved surface area$$=2\times\pi\times(5.25)^2\\=173.25\ m^2$$Mathematics

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