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Question

A hemispherical bowl is made of steel 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. [Use π = 227]


Solution

We have,Inner radius of the hemispherical bowl, r=5 cm andThickness of the bowl=0.25 cmAlso, the outer radius of the bowl, R=5+0.25=5.25 cmNow,The outer curved surface area of the bowl=2πR2=2×227×5.25×5.25=173.25 cm2

So, the outer curved surface area of the hemispherical bowl is 173.25 cm2.


Mathematics
RD Sharma (2017)
Standard IX

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