Question

# A hemispherical bowl is made of steel, $$0.25\ cm$$ thick. The inner radius of the bowl is $$5\ cm$$. Find the outer curved surface area of the bowl.

Solution

## Given:Thickness $$=0.25$$cmInner radius $$=5$$cm$$\therefore$$ Outer radius $$=5+0.25=5.25cm$$$$\Rightarrow$$Outer Curved Surface Area $$=2\pi {r}^{2}$$$$=2\times \cfrac{22}{7}\times 5.25\times 5.25$$$$=173.25$$MathematicsRS AgarwalStandard IX

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