Question

# A hemispherical bowl is made of steel, $0.25cm$ thick. The inner radius of the bowl is $5cm$. Find the outer curved surface of the bowl. (Assume $\mathrm{\pi }=\frac{22}{7}$)

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Solution

## The inner radius of the hemispherical bowl$=5cm$The thickness of the bowl $=0.25cm$The outer radius of the hemispherical bowl $=\left(5+0.25\right)=5.25cm$We know, the formula for the outer curved surface area of a hemispherical bowl $=2{\mathrm{\pi r}}^{2}$, where r is radius of the hemisphere$2{\mathrm{\pi r}}^{2}=2×\frac{22}{7}×5.25×5.25=173.25c{m}^{2}$Hence, the outer curved surface area of the bowl is $173.25c{m}^{2}$.

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