A hemispherical bowl is made of steel,0.25 cm thick.The inner radius of the bowl is 5 cm.Find the outer curved surface area of the bowl.

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Solution

Total diameter= 10 + 0.25 + 0.25
=10.5
Radius= 5.25
C.s.a
2 $π$ $r^{2}$ =173.25 $c m^{2}$

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A hemispherical bowl is made of steel,0.25 cm thick.The inner radius of the bowl is 5 cm.Find the outer curved surface area of the bowl.

Total diameter= 10 + 0.25 + 0.25 =10.5 Radius= 5.25 C.s.a 2πr2=173.25cm2

Total diameter= 10 + 0.25 + 0.25
=10.5
Radius= 5.25
C.s.a
2 $π$ $r^{2}$ =173.25 $c m^{2}$