A hockey ball of mass 200g is traveling at 10 m/s and is struck by a hockey stick, so as to return it along its original path with a velocity of 50 m/s. Calculate the change of momentum occurred in the motion of hockey ball by the force applied by the hockey stick.

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Solution

$Initial Situation: - ---------------- -$
Mass of the hockey ball $m = 200 g = 0.2 k g$
Velocity of the ball $v_{1} = 10 m / s$
Thus, initial momentum of the ball is $P_{1} = m v_{1} = 0.2 \times 10 = 2 k g - m / s$

$Final Situation: - --------------- -$
Mass of the hockey ball $m = 200 g = 0.2 k g$
Velocity of the ball $v_{2} = 50 m / s$
Thus, final momentum of the ball is $P_{2} = m v_{2} = 0.2 \times 50 = 10 k g - m / s$

The hockey ball is returned to its initial path after being hit by the stick. Therefore, the direction of the initial momentum and the final momentum is opposite.
$∴ The change in the momentum = Δ P = P_{2} - (- P_{1}) = P_{2} + P_{1} = 2 + 10 = 12 k g - m / s$

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