The correct options are B
If all the objects have same mass, the kinetic energy (K.E.) of all the objects will be same at the bottom of inclined plane C
Work done by the gravitational force between the top and bottom points will be same for all, if the masses are same. D
If cylindrical shell can roll on inclined plane, all other objects will also roll.
We know that for inclined plane condition, mgsinθ−f=ma
Now, to satisfy the condition of pure rolling a=rα
On substituting, we get f=mgsinθ1+mr2I
Therefore, on dividing both we get μ=tanθ1+mr2I
Thus MOI for hollow cylinder is maximium of all the three objects therefore maximium μ
is offered by the plane, so if it can roll all other objects will roll too.
Change in potential energy is same and no frictional loss in case of pure rolling, then applying energy conservation we can conclude that K.E. will be same at the bottom.