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A homogeneous solid cylinder of length L (L< H2) Cross-sectional area A5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L4  in the denser liquid as shown in the fig. The lower density liquid is open to atmosphere having pressure P0. Then density D of solid is given by


  1. AD


Solution

The correct option is C


Weight of cylinder = upthrust due to both liquids V×D×g=(A5.34L)×d×g+(A5.L4)×2d×g(A5.L)D.g=ALDg4D5=d4D=54d

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