Question

A horizontal jet of water with its cross-sectional area of 0.0028 m${}^2$ hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate is

• A. 90
• B. 80
• C. 70
• D. 60

Answer 1

The correct option is C 70


Force on plate = $\left({\rho }_{w}aV\right)V$

= ${\rho }_{w}a{V}^2$

= 1000 $\times$ 0.0028 $\times$ (5)${}^2$

= 70 N