A horse id tried to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope.find
(i) the area of that part of the field in which the horse can graze.

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Solution

REF.Image
Area is a quadrant of radius, r=5m
Area = $\frac{1}{4} π r^{2} = \frac{25 π}{4} m^{2}$

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Q. Question 8
A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see Fig. 12.11). Find:
(i) The area of that part of the field in which the horse can graze.

Q. A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see Fig below). Find the area of that part of the field in which the horse can graze.

A horse is tied to a peg at one corner of a square shaped grass field of side $15 m$ by means of a $5 m$ long rope. Find
(i) the area of that part of the field in which the horse can graze.
(ii) The increase in the grazing area if the rope were $10 m$ long instead of $5 m$ . (Use $π = 3.14$ )

A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see the given figure). Find

(i) The area of that part of the field in which the horse can graze.

(ii) The increase in the grazing area of the rope were 10 m long instead of 5 m.

[Use π = 3.14]

Q. A horse is tied to a pole fixed at one corner of a

30 m \times 30 m

square field of grass, by means of a

10 m

long rope. Find the area of the field, in which the horse can graze? (Take

π = 3.14

)

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A horse id tried to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope.find (i) the area of that part of the field in which the horse can graze.

REF.ImageArea is a quadrant of radius, r=5mArea = 14πr2=25π4m2

A horse id tried to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope.find
(i) the area of that part of the field in which the horse can graze.

REF.Image
Area is a quadrant of radius, r=5m
Area = $\frac{1}{4} π r^{2} = \frac{25 π}{4} m^{2}$