Question

A hotel building is in the form as shown alongside. The vertical cross section parallel to the width side of the building is a rectangle of size 6 m x 2 m mounted by a semicircle of radius 4 m. The inner measurements of a cuboid are 12 x 6 x 2 m. Find the volume.

Answer 1

Volume:
As the hotel building is of uniform cross-section: its volume $=$ Its area of cross section $\times$ its length
$=[6\times 2+\frac{1}{2}\times \frac{22}{7}\times (4{)}^2]\times 12$
$=37.14\times 12$
$=445.68m^3$