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Question

A hydrocarbon X adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X reacts with KMnO4 in presence of acid to give two moles of the same carboxylic acid. The structure of X is


A
CH2=CHCH2CH2CH3
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B
CH3CH2CH2CH=CHCH3
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C
CH3CH2CH=CHCH2CH3
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D
CH3CH=CHCH2CH2CH3
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Solution

The correct option is D CH3CH2CH=CHCH2CH3
Since it produces the same carboxylic acid, it should have a symmetrically centralised double bond(groups on either side of the double bond are the same). Using that concept, the answer is CH3CH2CH=CHCH2CH3

Chemistry

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