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Question

A hydrogen atom in the ground state absorbs $$10.2\space eV$$ of energy. The orbital angular momentum of the electron is increased by


A
1.05×1034 Js
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B
2.11×1034 Js
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C
3.16×1034 Js
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D
4.22×1034 Js
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Solution

The correct option is A $$1.05\times10^{-34}\space Js$$
After absorbing $$10.2\ eV$$, electron jumps into orbit with $$n=2$$.
Angular momentum increases by $${ L }_{ 2 }-{ L }_{ 1 }=\dfrac { 2h-h }{ 2\pi  } =\dfrac { h }{ 2\pi  }  =\dfrac { 6.625\times { 10 }^{ -34 } }{ 2\times 3.14 } =1.05\times { 10 }^{ -34 }\ Js$$

Physics

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