Question

A hydrogen atom in the ground state absorbs $10.2eV$ of energy. The orbital angular momentum of the electron is increased by

• A. $1.05\times {10}^{-34}Js$
• B. $2.11\times {10}^{-34}Js$
• C. $3.16\times {10}^{-34}Js$
• D. $4.22\times {10}^{-34}Js$

Answer 1

The correct option is A $1.05\times {10}^{-34}Js$

After absorbing $10.2eV$, electron jumps into orbit with $n=2$.
Angular momentum increases by $L_2-L_1=\frac{2h-h}{2\pi }=\frac{h}{2\pi }=\frac{6.625\times {10}^{-34}}{2\times 3.14}=1.05\times {10}^{-34}Js$