A hypothetical electromagnetic wave is shown below. Find out the frequency of the radiation.
A
3.47×1019 s−1
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B
6.49×1019 s−1
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C
2.47×1019 s−1
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D
5.52×1019 s−1
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Solution
The correct option is A3.47×1019 s−1 Wavelength (λ) is the distance between two successive peaks or two successive troughs in a wave. So, λ=4×2.16 pm=8.64 pm We know, c=λv therefore, v=cλ=3×1088.64×10−12=3.47×1019 s−1