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Question

A hypothetical electromagnetic wave is shown below. Find out the frequency of the radiation.

A
3.47×1019 s1
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B
6.49×1019 s1
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C
2.47×1019 s1
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D
5.52×1019 s1
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Solution

The correct option is A 3.47×1019 s1
Wavelength (λ) is the distance between two successive peaks or two successive troughs in a wave.
So, λ=4×2.16 pm=8.64 pm
We know, c=λv
therefore, v=cλ=3×1088.64×1012=3.47×1019 s1

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