Question

# A is a skew symmetric matrix such that $$A^TA = I$$, then $$A^{4n-1} (n \in N)$$ is equal to

A
AT
B
I
C
I
D
AT

Solution

## The correct option is D $$A^T$$$$A^T = - A$$ & $$A^TA = I$$$$\Rightarrow A^2 = -I \Rightarrow A^{4n} = I$$ $$\therefore A^{4n-1} = A^{-1} = A^T$$ Mathematics

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