CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A is elder to B by 2 years. A's father F is twice as old as A and B is twice as old as his sister S. If the ages of the father and sister differ by 40 years, find the age of A.

Open in App
Solution

Let a, b, f and s be the ages of A, B, F and S respectively.
A is elder to B by 2 years. So, a=b+2. ab=2
F is twice as old as A. So, f=2a.
B is twice as old as S. So, b=2s.
Finally, the ages of F and S differ by 40 years. So, fs=40.
Substituting f=2a and s=b2 into fs=40, we get 2ab2=40.
4ab=80.
Subtracting the equation ab=2 from 4ab=80, we get
3a=78.
a=26
So, the age of A is 26 years.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Writing a Quadratic Equation from the given Data
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon