Question

A jar contains 24 marbles of which some are green and others are blue. If a marble is drawn randomly from the jar, the probability that it is green is $\frac{2}{3}$. Find the probability of drawing a blue marble from the jar.

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{2}{3}$
• D. $\frac{1}{3}$

Answer 1

The correct option is D

$\frac{1}{3}$

Given,

Total number of marbles =24

P(green marbles)$=\frac{2}{3}$

We know that,

P(green marbles) + P(blue marbles) =1

Because the sum of probabilities of an event and its complementary event is always 1.

$\Rightarrow$ P(blue marbles) = 1 - P(green marbles) =$1-\frac{2}{3}=\frac{1}{3}$

Therefore, P( blue marbles) $=\frac{1}{3}$