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Question

A joker’s cap is in the form of a right circular cone of base radius 7cm and height 24cm. Find the area of the sheet required to make 10 such caps. (Assume π=227)


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Solution

Step 1: Find the slant height of the conical cap

Curved surface area of cone is πrl.

Since, Radius of conical cap (r) =7cm

Height of conical cap (h) =24cm

Area of the sheet required to make 1cap=πrl (where l is the slant height and l=r2+h2)

Now,

l=72+242l=49+576l=625l=25

Step 2: Find the area of sheet require to make 10 such caps

Area of the sheet required to make 1cap =πrl

=227×7×25=22×25=550cm2

So, area of the sheet required to make 10 such caps=10×550=5500cm2

Hence, area of the required sheet is 5500cm2


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