A juggler throws balls into air. He throws one whenever the previous one is at its highest point. How high do the balls rise if the throws $n$ balls each second.

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Solution

using third equation of motion,

$v^{2} = u^{2} - 2 g h$

$0 = {(\frac{g}{n})}^{2} - 2 g h$

${(\frac{g}{n})}^{2} = 2 g h$

$(\frac{g}{n^{2}}) = 2 h$

$∴ h = \frac{g}{2 n^{2}}$

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A juggler throws balls into air. He throws one whenever the previous one is at its highest point. How high do the balls rise if the throws n balls each second.

using third equation of motion,v2=u2−2gh0=(gn)2−2gh(gn)2=2gh(gn2)=2h∴h=g2n2

A juggler throws balls into air. He throws one whenever the previous one is at its highest point. How high do the balls rise if the throws $n$ balls each second.

using third equation of motion,

$v^{2} = u^{2} - 2 g h$

$0 = {(\frac{g}{n})}^{2} - 2 g h$

${(\frac{g}{n})}^{2} = 2 g h$

$(\frac{g}{n^{2}}) = 2 h$

$∴ h = \frac{g}{2 n^{2}}$