wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ladder 17 m long reaches a window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.

Open in App
Solution



Let AB denote the height of the window above the ground.
AC denotes the length of the wall.
BC denote the distance of the foot of the ladder from the building.
AB=15m
AC=17m

Triangle ABC forms a right angled triangle.
AC2=AB2+BC2 [Pythagoras theroem]
(17)2=(15)2+(BC)2
289=225+(BC)2
(BC)2=49
BC=49
BC=7

Hence, the distance of the foot of the ladder from the building is 7 m


flag
Suggest Corrections
thumbs-up
22
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Pythogoras Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon