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Question

A lift is accelerating upwards with 25 ms2. In lift's reference frame, a man of 50 kg will feel a pseudo force of in direction .

A
1250 N
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B
750 N
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C
upward
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D
downward
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Solution

The correct option is D downward
The pseudo force in a non-inertial frame is given by, Fpseudo=Ma
where, M = mass of an object in that frame
a = acceleration of the frame
Thus, F = 50 × 25 N
= 1250 N
The direction will be opposite to the acceleration of the frame. In this case it is vertically downwards.
Therefore, Fpseudo=1250N, downwards.

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