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Question

A lifting machine, having an efficiency of 80 % uses 2500 J of energy in lifting a 10 kg load over a certain height. If the load is now allowed to fall through that height freely, its velocity at the end of the fall will be
(take acceleration due to gravity as 10m/s2 )

A
10ms1
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B
15ms1
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C
20ms1
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D
25ms1
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Solution

The correct option is C 20ms1
1) Energy stored in the form of P.E=0.8×2500J
2)This energy will again be converted into K.E
i.e 12mv2=0.8×2500
12×10×v2=0.8×2500
v2=400
v=20 m/s

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