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AC Applied to a Resistor

A light bulb ...

Question

A light bulb is rated at $100 W$ for a $220 V$ supply. Find the rms current through the bulb:

0.25 A

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0.45 A

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0.65 A

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0.85 A

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Solution

The correct option is D $0.45 A$
$A n s w e r : -$ B
Power is given by:
$P = \frac{V^{2}}{R} 100 = \frac{(220)^{2}}{R} R = 484 Ω$

The rated voltage in bulb is rms voltage so using:
$V_{r m s} = I_{r m s} R$
$I_{r m s} = \frac{220}{484} = 0.45 A$

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