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Question

A light string fixed at one end to a clamp on ground passes over a fixed pulley and hangs at the other side. It makes an angle of 30 with the ground. A monkey of mass 5 kg climbs up the rope. The clamp can tolerate a vertical force of 40 N only. The maximum acceleration in upward direction with which the monkey can climb safely is (Neglect friction and take g=10 ms2)

  1. 2 ms2
  2. 8 ms2
  3. 4 ms2
  4. 6 ms2


Solution

The correct option is D 6 ms2
Let T be the tension in the string. The upward force exerted on the clamp is T sin 30=T2.

Given T2=40 N
T=80 N..............(1)
If a is the acceleration of monkey in upward direction.
a=T -mgm
a=80(5)(10)5=6 ms2
Hence, the correct answer is (C).

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