A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

Q. Two blocks of masses

m_{1} = m

and

m_{2} = 2 m

are connected by a light string passing over a smooth pulley. The mass

m_{1}

is placed on a smooth inclined plane of inclination

Θ = 30^{^{0}}

, If the system is released, the blocks move with an acceleration equal to:

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A light string passing over the smooth pulley connects two blocks of masses m1 and m2 (m2>m1) (vertically). If the acceleration of the system is g/8. Then the ratio of masses (m2m1) is:

The correct option is B 9:7motion of m1 implies T−m1g=m1g8→1m2g−T=m2g8→21+2⇒m2g−m1g=m1g8+m2g8m1m2=g−g8g+g8m1m2=79

A light string passing over the smooth pulley connects two blocks of masses $m_{1}$ and $m_{2}$ $(m_{2} > m_{1})$ (vertically). If the acceleration of the system is $g / 8$ . Then the ratio of masses ( $\frac{m_{2}}{m_{1}})$ is: