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Question

A line is drawn perpendicular to line y=5x, meeting the coordinate axes at A and B. If the area of triangle OAB is 10 sq. units where O is the origin, then the equation of drawn line is

A
3xy9
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B
x+5y=10
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C
x+4y=10
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D
x4y=10
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Solution

The correct option is B x+5y=10

Using the concept: line perpendicular to
ax+by+c=0
is bxay+c=0.

Let the required line be x+5y=c.

x+5y=cxc+yc5=1

x-intercept=c,y-intercept=c5

Now area of triangle =12×base×height area=12×c×c5=c210=10

c2=100 c=±10

the required line is x+5y=10 or x+5y+10=0


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