Question

A line makes an angle of ${60}^{\circ }$ with the positive direction of the x-axis. The slope of the line is

• A. $\frac{1}{\sqrt{3}}$
• B. $\sqrt{3}$
• C. 1

Answer 1

The correct option is B $\sqrt{3}$

Given, $\theta ={60}^{\circ }$

The slope of the line, $m=\tan \theta =\tan {60}^{\circ }$ = $\sqrt{3}$