A live load 20 kN/m, 6 m long, moves on simply supported girder AB 12 m long. For maximum bending moment to occur at 4 m from left end A. Where will the head of load be, as measured from A?

10 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8 m$

Let C is the section where B.M. is maximum hence
$A C = 4 m$
$B C = 8 m$
For the bending moment at C to be maximum
$\frac{W (L_{1} - a)}{A C} = \frac{W . a}{B C}$

$\frac{L_{1} - a}{a} = \frac{A C}{B C}$

$\frac{L_{1}}{a} - 1 = \frac{A C}{B C}$

$\frac{L_{1}}{a} = \frac{A C + B C}{B C}$

$a = \frac{L_{1} \times B C}{A C + B C} = \frac{6 \times 8}{4 + 8} = \frac{48}{12} = 4 m$

Hence head of UDL shall be AC + a = 4 + 4 = 8 m from 'A'.

Suggest Corrections

Similar questions

Q. A uniformly distributed load of 50 kN/m and 5 m long crosses a girder of span 15 m from left to right. What will be the maximum bending moment at a section 6 m from left end?

Four wheel loads of 6 kN, 4 kN,8kN and 5 kN cross a girder of 20 m span followed by uniformly distributed load of 4 kN/m and 4 m long with the 6 kN load leading. The magnitude of bending moment at a section 8 m from the left support is kNm.

Q. A simply supported beam

A C

of span 8 m is supported at end A and at point B distance 5 m from end A having a uniformly distributed load of intensity 4.8 kN/m over the supported span and a concentrated load of 20 kN at the free end. The point of location of maximum bending moment and its magnitude is:

Q. A train of concentrated loads as shown moves from left to right on a simply supported beam of span 6m. Determine the absolute maximum bending moment developed in the beam if the train can cross the beam

Q. A concentrated load P acts on a simply supported beam of span L at a distance L/3 from the left support. The bending moment at the point of application of the load is given by

Join BYJU'S Learning Program

A live load 20 kN/m, 6 m long, moves on simply supported girder AB 12 m long. For maximum bending moment to occur at 4 m from left end A. Where will the head of load be, as measured from A?

The correct option is C 8m Let C is the section where B.M. is maximum hence AC=4m BC=8m For the bending moment at C to be maximum W(L1−a)AC=W.aBC L1−aa=ACBC L1a−1=ACBC L1a=AC+BCBC a=L1×BCAC+BC=6×84+8=4812=4m Hence head of UDL shall be AC + a = 4 + 4 = 8 m from 'A'.