A log of wood of mass $20 k g$ float on water. The weight that can be put on the raft to make it just sink should be
$(w o o d = 600 k g m - 3)$

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Solution

Given,

Density of log, $ρ_{L} = 600 k g m^{- 3}$

Density of water, $ρ_{W} = 1000 k g m^{- 3}$

Weight of wood log, $= m g = 20 \times 10 = 200 N$

Volume of log is $V = \frac{m}{ρ_{L}} \frac{20}{600} = \frac{1}{30} m^{2}$

Weight of water displaced by log is $= ρ g V = 1000 \times 10 \times \frac{1}{30} = \frac{1000}{3} N$

Buoyancy force, $F_{b} = \frac{1000}{3} - 200 = 133.33 N$

Hence, weight greater then $133.33 N$ is required to sink the wood log.

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