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Question

A long solenoid has 500 turns. When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×103 Wb. The self-inductance of the solenoid is

A
1.0 H
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B
4.0 H
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C
2.5 H
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D
2.0 H
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Solution

The correct option is A 1.0 H
Given flux per turn =4×103i = 2 A
No of turns = 500
Total flux = 500×4×103 = 2 A
Flux, ϕ = Li2 = L×2L = 1 H





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