CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A long straight cylindrical wire of radius R carries a current distributed uniformly over its cross section. Find the locations where the magnetic field is maximum and minimum.

Open in App
Solution

Let total current through the wire be I.
To get the magnetic field intensity we will be applying Ampere's Circuit as law.
Case 1
For r.R
B.dl=μ0I
we will take the loop in the from circle of radius r
B.dl=μ0I
B.2πr=μ0I
B=μ0I2πr
Case2
r=R
We will take ampreres loop as a circle of radius R
B.dl=μ0IB.2πR=μ0I
B=μ0I2πR
Case 3
r<R
Here we eill take an ampere loop of radius r
current through the loop =IπR2×πr2
=Ir2R2
B.dl=μ0i
B.2πr=μ0I r2R2B=μ0I r2πR2
Magnetic Field will be maximum at R
Magnetic Field will be minimum at r=0 at the centre
(If infinete distance is not considered)


1432469_1019223_ans_3b4fae0410df40b09ce4592ec617dfc4.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque on a Magnetic Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon