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Question

A long straight wire carries a current of $$10 A$$. An electron travels with a velocity of $$5 \times 10^{6} m/s$$ parallel to the wire $$0.1 m$$ from it, and in a direction opposite to the current. The force does the magnetic field of current exert on the electron is :


A
1.6×1019N
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B
3.2×1017N
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C
1.6×1017N
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D
3.2×1019N
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Solution

The correct option is C $$1.6\times 10^{-17}N$$
magnetic field due to straight wire =$$\dfrac{\mu _{0}i}{2\pi r}$$

|B| at $$0.1m$$ from wire =$$\dfrac{2\times 10_{-7}\times 10}{0.1}$$  =$$2\times 10^{-5}T$$

force for electron$$=evB$$
=$$1.6\times 10^{-19}\times 5\times 10^{6}\times 2\times 10^{-5}$$
=$$1.6\times 10^{-17}N$$

Physics

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