Question

# A long straight wire carries a current of $$50\, A$$. An electron moving at $$10^7\, m/s$$ is $$5\, cm$$ away from the wire. The force acting on electron if its velocity is directed towards the wire will be :

A
1.6×106N
B
3.2×1016N
C
4.8×1016N
D
1.8×1016N

Solution

## The correct option is C $$3.2\times 10^{-16}\, N$$Given: Current in wire= 50A            Speed of electron=$$10^{7}ms^{-1}$$Solution: Let us assume the current is directed in +y direction.As we know, magnetic field due to straight wire is given by,$$B=\frac{\mu _{0}i}{2\pi r}$$$$=\frac{4\pi \times 10^{-7}\times 50}{2\pi \times 0.05}$$$$=0.0002T$$According to question, v and B are perpendicular to each other.$$F=qvb$$Substituting the values we get,$$=1.6\times 10^{-19}\times 10^{7}\times 0.0002$$$$=3.2\times 10^{-16}N$$Hence, the correct option is (B).Physics

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