A long wire of some length is cut into small pieces of 216 cm, leaves a small piece of 89 cm. If this part were cut into equal pieces if 18 cm, therefore,find the length of the leftover wire.

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Solution

Dear student
$Leftover part of the wire in the 89 cm wire = \frac{89}{18} = 4 \frac{17}{18} So, a piece of 17 cm was leftover from a piece of 89 cm piece .$
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A long wire of some length is cut into small pieces of 216 cm, leaves a small piece of 89 cm. If this part were cut into equal pieces if 18 cm, therefore,find the length of the leftover wire.

Dear student Leftover part of the wire in the 89 cm wire=8918=41718So, a piece of 17cm was leftover from a piece of 89cm piece. Regards

Dear student
$Leftover part of the wire in the 89 cm wire = \frac{89}{18} = 4 \frac{17}{18} So, a piece of 17 cm was leftover from a piece of 89 cm piece .$
Regards