A longitudinal wave travels through a coiled spring at a speed of $4 m s^{- 1}$ . The distance between two consecutive compression is $20 c m$ . Find the frequency of the wave?

15 hertz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 hertz

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 hertz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 hertz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
20 hertz

We know that,

Wavelength = distance between two consecutive compressions $(h e r e w a v e l e n g t h = 20 c m = 0.2 m)$

Also, $s p e e d = f r e q u e n c y \times w a v e l e n g t h$

or, $F r e q u e n c y = \frac{s p e e d}{w a v e l e n g t h}$

= $\frac{4}{0.2}$ = $20 h e r t z$

Suggest Corrections

Similar questions

The longitudinal waves travel in a coiled spring at a rate of $4 m / s$ . The distance between two consecutive compressions is $20 c m$ . Find the frequency of the wave?