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Question

A machine gun fires a bullet of mass $$40 g$$ with a velocity $$1200 \,ms^{-1}$$. The man holding it can exert a maximum force of $$144 N$$ on the gun. How many bullets can he fire per second at the most?


A
2
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B
4
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C
1
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D
3
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Solution

The correct option is D $$3$$
Given :     Mass of one bullet    $$m  = 40  $$ $$gm$$   $$ = 0.04$$ $$kg$$
                 Velocity of bullet      $$v = 1200$$  $$ms^{-1}$$
                 Maximum exerted by man  $$F = 144$$ N
Let the total number of bullets fired per sec be  $$n$$
Using       $$F  = \int P   dt$$            $$\implies  F = P  \Delta t$$
 Thus this force balances the net linear momenta offered by the bullets in one sec.
$$\therefore$$   $$F = nmv$$
$$144  = n  (0.04) (1200)$$                $$\implies  n = 3$$  bullets per sec

Physics

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