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Question

A machine has a velocity ratio of 4. It is used to raise a load of 400N by 4m using an effort 20kgf. Find the work done on the machine. Take g = 10 m/s2​.



A

1600 J

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B

3200 J

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C

6400 J

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D

2000 J

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Solution

The correct option is B

3200 J


Work obtained from machine is = Load × displacement = 400 × 4 = 1600 J,

 M.A = loadeffort = 400200 = 2,

Efficiency = M.AV.R = 24 = 12,

Percentage efficiency = 12 × 100% = 50%,

Work done on the machine (input) = outputefficiency = 1600(1/2) = 3200 J


Physics

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