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Question

A man bought two transistors which cost him $$Rs. 720.$$ He sold one of them at a loss of $$15\%$$ and the other at a gain of $$19\%.$$ If the selling price of both the transistors is same, find the cost price of each.


A
Rs.420;Rs.300
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B
Rs.440;Rs.320
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C
Rs.470;Rs.380
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D
Rs.490;Rs.410
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Solution

The correct option is A $$Rs. 420; Rs.300$$
Let the cost price of one transistor is $$x  Rs.$$
Then cost price of another transistor$$=720-x   Rs.$$
Then according to the question
$$\Rightarrow \dfrac{85}{100}\times x=\left(720-x  \right)\dfrac{119}{100}$$
$$\Rightarrow \dfrac{17x}{20}= \dfrac{119(720-x)}{100}$$
$$\Rightarrow 17x \times 100=119\times 20\times (720-x)$$
$$\Rightarrow 17x\times 5=119\times (720-x)$$
$$\Rightarrow 85x=85680-119x$$
$$\Rightarrow 85x+119x=85680$$
$$\Rightarrow 204x=85680$$
$$\Rightarrow x=\dfrac{85680}{204}\Rightarrow 420$$
Hence C.P of first transistor$$ =420  Rs.$$
C.P of another Transistor$$=720-420=300  Rs.$$

Mathematics

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