Question

A man bought two transistors which cost him $Rs.720.$ He sold one of them at a loss of $15\%$ and the other at a gain of $19\%.$ If the selling price of both the transistors is same, find the cost price of each.

• A. $Rs.420;Rs.300$
• B. $Rs.440;Rs.320$
• C. $Rs.470;Rs.380$
• D. $Rs.490;Rs.410$

Answer 1

The correct option is A $Rs.420;Rs.300$

Let the cost price of one transistor is $xRs.$

Then cost price of another transistor$=720-xRs.$

Then according to the question

$\Rightarrow \frac{85}{100}\times x=(720-x)\frac{119}{100}$

$\Rightarrow \frac{17x}{20}=\frac{119(720-x)}{100}$

$\Rightarrow 17x\times 100=119\times 20\times (720-x)$

$\Rightarrow 17x\times 5=119\times (720-x)$

$\Rightarrow 85x=85680-119x$

$\Rightarrow 85x+119x=85680$

$\Rightarrow 204x=85680$

$\Rightarrow x=\frac{85680}{204}\Rightarrow 420$

Hence C.P of first transistor$=420Rs.$

C.P of another Transistor$=720-420=300Rs.$