Question

# A man bought two transistors which cost him $$Rs. 720.$$ He sold one of them at a loss of $$15\%$$ and the other at a gain of $$19\%.$$ If the selling price of both the transistors is same, find the cost price of each.

A
Rs.420;Rs.300
B
Rs.440;Rs.320
C
Rs.470;Rs.380
D
Rs.490;Rs.410

Solution

## The correct option is A $$Rs. 420; Rs.300$$Let the cost price of one transistor is $$x Rs.$$Then cost price of another transistor$$=720-x Rs.$$Then according to the question$$\Rightarrow \dfrac{85}{100}\times x=\left(720-x \right)\dfrac{119}{100}$$$$\Rightarrow \dfrac{17x}{20}= \dfrac{119(720-x)}{100}$$$$\Rightarrow 17x \times 100=119\times 20\times (720-x)$$$$\Rightarrow 17x\times 5=119\times (720-x)$$$$\Rightarrow 85x=85680-119x$$$$\Rightarrow 85x+119x=85680$$$$\Rightarrow 204x=85680$$$$\Rightarrow x=\dfrac{85680}{204}\Rightarrow 420$$Hence C.P of first transistor$$=420 Rs.$$C.P of another Transistor$$=720-420=300 Rs.$$Mathematics

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