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Question

A man fires a gun while standing between 2 parallel hills. If he hears the first echo after 2s and second echo after 3s .then what is the distance between the hill (velocity of sound is 330m/s)


Solution

Time of echo = 2 s and 2.5 s

speed of sound = 330 m/s

Distance of first cliff   =(v×t)/2=)330×2)/2=330m

Distance of second cliff  =(v×t)/2=(330×3)/2=495m

Distance between cliffs = 330 + 495 = 825 m


 

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