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Question

A man in a balloon rising vertically with an acceleration of 4.9m/s​​​​​​2 releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is(g=9.8)


Solution

We found a similar question to the one that you posted. Please check it out here.

Height travelled by ball (with balloon) in 2 sec
h1=12at2=12×4.9×22=9.8m

Velocity of the balloon after 2 sec

v=at=4.9×2=9.8ms

Now if the ball is released from the balloon then it acquire same velocity in upward direction. 

Let it move up to maximum height h2

v2=u22gh20=(9.8)22×(9.8)×h2

h2=4.9m


Greatest height above the ground reached by the ball = h1+h2=9.8+4.9=14.7m

Physics

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