A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Let the son's present age be x years. Then, man's present age = (x + 30) years.
(x + 30) + 2 = 2(x + 2)
x + 32 = 2x + 4
x = 28
The present age of a man is 3 years more than 3 times the age of his son. 3 years hence , the man's age will be 10 years more than twice the age of his son. Determine their present ages.