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Question

A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of 2 m/s2, then the weight recorded in the machine will be (g=10 m/s)2

A
32 kg
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B
40 kg
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C
42 kg
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D
48 kg
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Solution

The correct option is D 48 kg
When man is stationary
his FBD
N=mg
m=Ng=40 kg
When lift accelerates, Pseudo force acts as lift is non-inertial frame.
FBD in non-inertial frame

N=m(g+a)
N=40(g+a)
Mass reading Ng=40(g+a)g=40(1210)=48 kg

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