Question

# A man of 50 kg is standing at one end on a boat of length 25 m and mass 200 kg.If he starts running and when he reaches the other end , he has a velocity $$2ms^{-1}$$ with respect to the boat.The final velocity of the boat is (in $$ms^{-1}$$).

A
2/5
B
2/3
C
8/5
D
8/3

Solution

## The correct option is A 2/5Let final velocity of boat be $$v$$.So velocity of man with respect to ground is $$2+v$$As Center-of-mass of system should remain at rest, in absence of external force, $$50(2+v) + 200v = 0\implies v=-\dfrac{2}{5}m/s$$negative sign idicates that the velocity of boat is in opposite direction to that of the man.Physics

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