A man of 50 kg is standing at one end on a boat of length 25 m and mass 200 kg.If he starts running and when he reaches the other end , he has a velocity 2ms−1 with respect to the boat.The final velocity of the boat is (in ms−1).
A
2/5
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B
2/3
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C
8/5
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D
8/3
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Solution
The correct option is A 2/5 Let final velocity of boat be v.
So velocity of man with respect to ground is 2+v
As Center-of-mass of system should remain at rest, in absence of external force,
50(2+v)+200v=0⟹v=−25m/s
negative sign idicates that the velocity of boat is in opposite direction to that of the man.