A man of 80kg attempts to jump from a small boat of mass 40kg on to the shore. He can generate a relative velocity of 6m/s between himself and boat. His velocity towards the shore is:
A
4m/s
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B
8m/s
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C
2m/s
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D
3m/s
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Solution
The correct option is B2m/s Mm=80kg
MB=40kg
VmB=6m/s
let velocity of man is Vm
velocity of boat = −VB
Since there is no external force in jumping direction so we can apply momentum conservation.